class Array<T>
Available on all platforms
An Array is a storage for values. You can access it using indexes or with its API.
Instance Fields
function concat(a:Array<T>):Array<T>
Returns a new Array by appending the elements of a
to the elements of
this
Array.
This operation does not modify this
Array.
If a
is the empty Array []
, a copy of this
Array is returned.
The length of the returned Array is equal to the sum of this.length
and a.length
.
If a
is null
, the result is unspecified.
Returns a shallow copy of this
Array.
The elements are not copied and retain their identity, so
a[i] == a.copy()[i]
is true for any valid i
. However,
a == a.copy()
is always false.
function filter(f:T ->Bool):Array<T>
Returns an Array containing those elements of this
for which f
returned true.
The individual elements are not duplicated and retain their identity.
If f
is null, the result is unspecified.
function indexOf(x:T, ?fromIndex:Int = null):Int
Returns position of the first occurense of x
in this
Array, searching front to back.
If x
is found by checking standard equality, the function returns its index.
If x
is not found, the function returns -1.
If fromIndex
is specified, it will be used as the starting index to search from,
otherwise search starts with zero index. If it is negative, it will be taken as the
offset from the end of this
Array to compute the starting index. If given or computed
starting index is less than 0, the whole array will be searched, if it is greater than
or equal to the length of this
Array, the function returns -1.
function insert(pos:Int, x:T):Void
Inserts the element x
at the position pos
.
This operation modifies this
Array in place.
The offset is calculated like so:
- If
pos
exceedsthis.length
, the offset isthis.length
. -
If
pos
is negative, the offset is calculated from the end ofthis
Array, i.e.this.length + pos
. If this yields a negative value, the offset is 0. - Otherwise, the offset is
pos
.
If the resulting offset does not exceed this.length
, all elements from
and including that offset to the end of this
Array are moved one index
ahead.
function join(sep:String):String
Returns a string representation of this
Array, with sep
separating
each element.
The result of this operation is equal to Std.string(this[0]) + sep +
Std.string(this[1]) + sep + ... + sep + Std.string(this[this.length-1])
If this
is the empty Array []
, the result is the empty String ""
.
If this
has exactly one element, the result is equal to a call to
Std.string(this[0])
.
If sep
is null, the result is unspecified.
function lastIndexOf(x:T, ?fromIndex:Int = null):Int
Returns position of the last occurense of x
in this
Array, searching back to front.
If x
is found by checking standard equality, the function returns its index.
If x
is not found, the function returns -1.
If fromIndex
is specified, it will be used as the starting index to search from,
otherwise search starts with the last element index. If it is negative, it will be
taken as the offset from the end of this
Array to compute the starting index. If
given or computed starting index is greater than or equal to the length of this
Array,
the whole array will be searched, if it is less than 0, the function returns -1.
function map<S>(f:T ->S):Array<S>
Creates a new Array by applying function f
to all elements of this
.
The order of elements is preserved.
If f
is null, the result is unspecified.
Removes the last element of this
Array and returns it.
This operation modifies this
Array in place.
If this
has at least one element, this.length
will decrease by 1.
If this
is the empty Array []
, null is returned and the length
remains 0.
Adds the element x
at the end of this
Array and returns the new
length of this
Array.
This operation modifies this
Array in place.
this.length
increases by 1.
Removes the first occurence of x
in this
Array.
This operation modifies this
Array in place.
If x
is found by checking standard equality, it is removed from this
Array and all following elements are reindexed acoordingly. The function
then returns true.
If x
is not found, this
Array is not changed and the function
returns false.
Reverse the order of elements of this
Array.
This operation modifies this
Array in place.
If this.length < 2
, this
remains unchanged.
Removes the first element of this
Array and returns it.
This operation modifies this
Array in place.
If this
has at least one element, this
.length and the index of each
remaining element is decreased by 1.
If this
is the empty Array []
, null
is returned and the length
remains 0.
function slice(pos:Int, ?end:Int = null):Array<T>
Creates a shallow copy of the range of this
Array, starting at and
including pos
, up to but not including end
.
This operation does not modify this
Array.
The elements are not copied and retain their identity.
If end
is omitted or exceeds this.length
, it defaults to the end of
this
Array.
If pos
or end
are negative, their offsets are calculated from the
end of this
Array by this.length + pos
and this.length + end
respectively. If this yields a negative value, 0 is used instead.
If pos
exceeds this.length
or if end
exceeds or equals pos
,
the result is []
.
function sort(f:T ->T ->Int):Void
Sorts this
Array according to the comparison function f
, where
f(x,y)
returns 0 if x == y, a positive Int if x > y and a
negative Int if x < y.
This operation modifies this
Array in place.
The sort operation is not guaranteed to be stable, which means that the
order of equal elements may not be retained. For a stable Array sorting
algorithm, haxe.ds.sort.MergeSort.sort()
can be used instead.
If f
is null, the result is unspecified.
function splice(pos:Int, len:Int):Array<T>
Removes len
elements from this
Array, starting at and including
pos
, an returns them.
This operation modifies this
Array in place.
If len
is < 0 or pos
exceeds this
.length, the result is the empty
Array [].
If pos
is negative, its value is calculated from the end of this
Array by this.length + pos
. If this yields a negative value, 0 is
used instead.
If the sum of the resulting values for len
and pos
exceed
this.length
, this operation will affect the elements from pos
to the
end of this
Array.
The length of the returned Array is equal to the new length of this
Array subtracted from the original length of this
Array. In other
words, each element of the original this
Array either remains in
this
Array or becomes an element of the returned Array.